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Sutherland law

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Sutherland's law for molecular viscosity coefficient is given by

$\mu = \mu_{\mbox{ref}} \left( \frac{T}{T_{\mbox{ref}}} \right)^{3/2} \frac{ T_{\mbox{ref}} + T_s }{ T + T_s}$

For air,

$T_s = 110.6 K$
$T_{\mbox{ref}} = 273.15 K$
$\mu_{\mbox{ref}} = 1.716 \times 10^{-5} kg/(m-s)$

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