2-D vortex in isentropic flow
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Roberthealy1 (Talk | contribs) m (I think that this article may qualify as a stub, as it represents a POV; "one choice". An explanation of what the test is and what it can be used for would be worthwhile) |
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(\delta u, \delta v) &=& \frac{\beta}{2\pi} \exp\left( \frac{1-r^2}{2} | (\delta u, \delta v) &=& \frac{\beta}{2\pi} \exp\left( \frac{1-r^2}{2} | ||
\right) [ -(y-y_o), (x-x_o) ] \\ | \right) [ -(y-y_o), (x-x_o) ] \\ | ||
- | \rho &=& \left[ 1 - \frac{ (\gamma-1)\beta^2}{8\gamma\pi} \exp\left( | + | \rho &=& \left[ 1 - \frac{ (\gamma-1)\beta^2}{8\gamma\pi^2} \exp\left( |
1-r^2\right) \right]^{\frac{1}{\gamma-1}} \\ | 1-r^2\right) \right]^{\frac{1}{\gamma-1}} \\ | ||
p &=& \frac{ \rho^\gamma }{\gamma} | p &=& \frac{ \rho^\gamma }{\gamma} |
Revision as of 14:35, 6 January 2012
The test case involves convection of an isentropic vortex in inviscid flow. The free-stream conditions are
Perturbations are added to the free-stream in such a way that there is no entropy gradient in the flow-field. The perturbations are given by
where
is distance from the vortex center .
One choice for the domain and parameters is:
As a result of isentropy, the exact solution corresponds to a pure advection of the vortex at the free-stream velocity. Further details can be found in Yee et al. (1999).
References
- Yee, H-C., Sandham, N. and Djomehri, M., (1999), "Low dissipative high order shock-capturing methods using characteristic-based filters", JCP, Vol. 150.