Smagorinsky-Lilly model

(Difference between revisions)

Latest revision as of 19:42, 19 June 2009

The Smagorinsky model could be summarised as:

$\tau _{ij} - \frac{1}{3}\tau _{kk} \delta _{ij} = - 2\left( {C_s \Delta } \right)^2 \left| {\bar S} \right|S_{ij}$

In the Smagorinsky-Lilly model, the eddy viscosity is modeled by

$\mu _{sgs} = \rho \left( {C_s \Delta } \right)^2 \left| {\bar S} \right|$

Where the filter width is usually taken to be

$\Delta = \left( \mbox{Volume} \right)^{\frac{1}{3}}$

and

$\bar S = \sqrt {2S_{ij} S_{ij} }$

The effective viscosity is calculated from

$\mu _{eff} = \mu _{mol} + \mu _{sgs}$

The Smagorinsky constant usually has the value:

$C_s = 0.1 - 0.2$

@@ Line 1: / Line 1: @@
-In the Smagorinsky-Lilly model, the eddy-viscosity is modeled by  <br>
+The Smagorinsky model could be summarised as:
+:<math>
+\tau _{ij}  - \frac{1}{3}\tau _{kk} \delta _{ij}  =  - 2\left( {C_s \Delta } \right)^2 \left| {\bar S} \right|S_{ij}
+</math> <br>
+In the Smagorinsky-Lilly model, the eddy viscosity is modeled by  <br>
 :<math>
-\mu _{sgs}  = \rho \left( {C_s \bar \Delta } \right)^2 \left| {\bar S} \right|
+\mu _{sgs}  = \rho \left( {C_s \Delta } \right)^2 \left| {\bar S} \right|
 </math>
 <br>
-Where
+Where the filter width is usually taken to be
 :<math>
-\bar \Delta  = \nabla ^{\frac{1}{3}}
+ \Delta  = \left( \mbox{Volume} \right)^{\frac{1}{3}}
 </math>
 <br>
@@ Line 21: / Line 26: @@
 \mu _{eff}  = \mu _{mol}  + \mu _{sgs}
 </math>
-The Smogorinsky constant usually have the value:
+The Smagorinsky constant usually has the value:
 :<math>
 C_s  = 0.1 - 0.2
 </math>